Die Zertifikat für Microsoft 070-461 beteudet einen neuen Markstein im Leben. Man wird im Beruf befördert. Die Arbeitsaussichten verbessern sich. Jeder IT-Fachmann träumt davon. Es ist allen bekannt, dass solche Prüfung schwer zu bestehen ist. In Wirklichkeit sind zahlreiche Prüflinge in der Prüfung durchgefallen. Wenn man sich gar nicht um die Prüfung bemüht, fällt einem noch schwerer. Die Zertifizierungsprüfung für Microsoft 070-461 verlangt jedoch umfangreiche Fachkenntnisse. Unser Pass4Test bitet Ihnen einen kürzeren Weg zu der Microsoft 070-461 Zertifizierung. In unserer Website gibt es viele Trainingsinstrumente für die Microsoft 070-461 Zertifizierungsprüfung, die Ihnen zum Bestehen der Prüfung unter Garantie helfen. Außerdem können Sie dabei viel Zeit ersparen. So ist es Ihnen ganz preisgünstig, dass man per Pass4Test mit weniger Zeit und Geld ein wertvolles Zertifikat bekommt.
Kein Wunder, dass die Microsoft 070-461-Prüfungsschulungsunterlagen von Pass4Test von der Mehrheit der Kandidaten gelobt werden. Das zeigt, dass die Schulungsunterlagen doch zuverlässig sind und den Kandidaten tatsächlich Hilfe leisten können. Die Kandidaten sind in der Lage, die Prüfung unbesorgt zu bestehen. Im vergleich zu anderen Websites ist Pass4Test immer noch der Best-Seller auf dem Market. Unter den Kunden hat der Pass4Test einen guten Ruf und wird von vielen anerkannt. Wenn Sie an der Microsoft 070-461-Prüfung teilnehmen wollen, klicken Sie doch schnell Pass4Test. Ich glaube, Sie werden sicher was bekommen, was Sie wollen. Sonst würden Sie sicher bereuen. Wenn Sie ein professionelle IT-Experte werden wollen, dann fügen Sie es schnell in den Warenkorb.
Exam Code: 070-461
Prüfungsname: Querying Microsoft SQL Server 2012
Aktulisiert: 2014-02-28
Nummer: 98 Q&As
Es gibt eine Menge von Websites, die Microsoft 070-461 Zertifizierungsprüfung und andere Schulungsunterlagenbieten bieten. Aber Pass4Test ist die einzige Website, die Ihnen Schulungsunterlagen zur Microsoft 070-461Zertifizierungsprüfung mit hoher Qualität bieten. Unter der Anleitung und Hilfe von Pass4Test können Sie zum ersten Mal die Microsoft 070-461 Prüfung bestehen. Die Fragen und die Antworten von Pass4Test werden von den lebendigen IT-Experten nach ihren umfangreichen Wissen und Erfahrungen bearbeitet. Sie werden Sie sicher im IT-Bereich sehr fördern.
Kümmern Sie sich darum, die ausgezeichnete Microsoft 070-461 Zertifizierung Prüfungsunterlagen zu finden? Machen Sie sich jetzt keine Sorge, alle Prüfungsfragen sind an Pass4Test vorhanden. Pass4Test hat eine hocheffektive Lernmethode für Microsoft 070-461 Prüfungsteilnehmer geschaffen. Es ist sehr müde, wenn Sie die Prüfungsfragen während jobben vorbereiten. Um Ihre Zeit für die Prüfungsvorbereitung zu sparen, Pass4Test bietet Ihnen Microsoft 070-461 dumps, mit denen Sie in kurzer Zeit diese Prüfung bestehen können. Diese dumps beinhalten alle mögliche Fragen in den aktuellen Prüfungen. So, Sie können Microsoft 070-461 Zertifizierungsprüfung bestehen, solange sie diese dumps gut lernen.
070-461 prüfungsfragen Demo kostenlos downloden: http://www.pass4test.de/070-461.html
NO.1 You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown
in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to
1 in the following XML format.
Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers-CustomerId
WHERE Customers.CustomerId = 1
FOR XML RAW
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers=CustomerId = 1
FOR XML RAW, ELEMENTS
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerXd - Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId- 1
FOR XML AUTO
F.SELECT Name, Country, Crderld, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
H. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount
FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
Answer: E
Microsoft 070-461 070-461 070-461 echte fragen
NO.2 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the top half of the students arranged by their average marks must be given a rank
of 1 and the remaining students must be given a rank of 2.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code,
DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value
FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: D
Microsoft testantworten 070-461 zertifizierungsfragen 070-461
NO.3 You develop a Microsoft SQL Server 2012 server database that supports an application. The application
contains a table that has the following definition:
CREATE TABLE Inventory
(ItemID int NOT NULL PRIMARY KEY,
ItemsInStore int NOT NULL,
ItemsInWarehouse int NOT NULL)
You need to create a computed column that returns the sum total of the ItemsInStore and
ItemsInWarehouse values for each row.
The new column is expected to be queried heavily, and you need to be able to index the column.
Which Transact-SQL statement should you use?
A. ALTER TABLE Inventory
All TotalItems AS Item3lnStore + ItemsInWarehouse
B. ALTER TABLE Inventory
ADD TotalItems AS ItemsInStore + ItemsInWarehouse PERSISTED
C. ALTER TABLE Inventory
ADD TotalItems AS SUM (ItemsInStore, ItemsInWarehouse) PERSISTED
D. ALTER TABLE Inventory
All TotalItems AS SUM (ItemsInStore, ItemsInWarehouse)
Answer: C
Microsoft prüfung 070-461 070-461 070-461 070-461 prüfungsfragen 070-461 zertifizierungsfragen
NO.4 You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown
in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerIdvalue set to
1 in the following XML format.
Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers-CustomerId
WHERE Customers.CustomerId = 1
FOR XML RAW
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers=CustomerId = 1
FOR XML RAW, ELEMENTS
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerXd - Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId- 1
FOR XML AUTO
F. SELECT Name, Country, Crderld, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
H. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount
FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
Answer: C
Microsoft exam fragen 070-461 originale fragen 070-461 zertifizierungsfragen 070-461 prüfung 070-461 zertifizierungsantworten
NO.5 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
Students must be ranked based on their average marks.
If one or more students have the same average, the same rank must be given to these students.
Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code,
DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value
FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: A
Microsoft prüfungsfragen 070-461 dumps 070-461 070-461 prüfungsfragen
NO.6 You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown
in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to
1 in the following XML format.
<row OrderId= "1" orderDate="2000-01-01T00:00:00", Amount="3400.00" Name="Customer A"
Country="Australia" />
<row OrderId="2" OrderDate="2001-01-01T00:00:00" Amount="4300.00" Name="Customer A"
Country-"Australia" />
Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers-CustomerId
WHERE Customers.CustomerId = 1
FOR XML RAW
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers=CustomerId = 1
FOR XML RAW, ELEMENTS
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId - Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId- 1
FOR XML AUTO
F. SELECT Name, Country, Crderld, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
H. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount
FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
Answer: A
Microsoft originale fragen 070-461 070-461 070-461 antworten 070-461 originale fragen
NO.7 You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown
in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to
1 in the following XML format.
Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers-CustomerId
WHERE Customers.CustomerId = 1
FOR XML RAW
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers=CustomerId = 1
FOR XML RAW, ELEMENTS
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FOR XML AUTO
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerXd - Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId- 1
FOR XML AUTO
F.SELECT Name, Country, Crderld, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML AUTO, ELEMENTS
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
H. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount
FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId= 1
FOR XML PATH ('Customers')
Answer: D
Microsoft dumps 070-461 zertifizierungsfragen 070-461 070-461
NO.8 You develop a Microsoft SQL Server 2012 database that contains a table named Customers.
The Customers table has the following definition:
You need to create an audit record only when either the MobileNumber or HomeNumber column is
updated.
Which Transact-SQL query should you use?
A. CREATE TRIGGER TrgPhoneNumberChange
ON Customers FOR UPDATE
AS
IF COLUMNS_UPDATED (HomeNumber, MobiieNumber)
- - Create Audit Records
B. CREATE TRIGGER TrgPhoneNumberChange
ON Customers FOR UPDATE
AS
IF EXISTS( SELECT HomeNumber from inserted) OR
EXISTS (SELECT MobileNumber FROM inserted)
- - Create Audit Records
C. CREATE TRIGGER TrgPhoneNumberChange
ON Customers FOR UPDATE
AS
IF COLUMNS_CHANGED (HomeNumber, MobileNumber)
- - Create Audit Records
D. CREATE TRIGGER TrgPhoneNumberChange
ON Customers FOR UPDATE
AS
IF UPDATE (HomeNumber) OR UPDATE (MobileNumber)
- - Create Audit Records
Answer: D
Microsoft 070-461 070-461
NO.9 DRAG DROP
You use a Microsoft SQL Server 2012 database.
You need to create an indexed view within the database for a report that displays Customer Name and the
total revenue for that customer.
Which four T-SQL statements should you use? (To answer, move the appropriate SQL statements from
the list of statements to the answer area and arrange them in the correct order.)
Answer:
NO.10 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects.
You need to retrieve the students who scored the highest marks for each subject along with the marks.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code,
DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value
FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: F
Microsoft 070-461 dumps 070-461 zertifizierung 070-461
Pass4Test bietet Ihnen die neusten SY0-301 exam Unterlagen und 000-318 pdf Fragen & Antworten mit hoher Qualität. Unser 156-915.76 zertifizierung und CAT-380 prüfung Lernführung können Ihnen hilfen, die aktuellen Prüfungen zu bestehen. Hochqualitative 700-410 dumps Training Unterlagen können Ihnen gewährleisten, leichter und schneller, diese Prüfung zu bestehen. Es ist sehr einfach für Sie, die Zertifizierung zu bekommen.
Artikel Link: http://www.pass4test.de/070-461.html